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56554143642253 is a prime number
BaseRepresentation
bin11001101101111100010011…
…01001000111001010001101
321102020112010111201112111001
430312332021221013022031
524403040341233023003
6320140340453500301
714624621254241245
oct1466761151071215
9242215114645431
1056554143642253
11170245287a4814
1264146a4341691
13257305727607a
14dd73413b2b25
15681182c6b61d
hex336f89a4728d

56554143642253 has 2 divisors, whose sum is σ = 56554143642254. Its totient is φ = 56554143642252.

The previous prime is 56554143642247. The next prime is 56554143642263. The reversal of 56554143642253 is 35224634145565.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 54207481180329 + 2346662461924 = 7362573^2 + 1531882^2 .

It is a cyclic number.

It is not a de Polignac number, because 56554143642253 - 237 = 56416704688781 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 56554143642194 and 56554143642203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (56554143642203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28277071821126 + 28277071821127.

It is an arithmetic number, because the mean of its divisors is an integer number (28277071821127).

Almost surely, 256554143642253 is an apocalyptic number.

It is an amenable number.

56554143642253 is a deficient number, since it is larger than the sum of its proper divisors (1).

56554143642253 is an equidigital number, since it uses as much as digits as its factorization.

56554143642253 is an evil number, because the sum of its binary digits is even.

The product of its digits is 51840000, while the sum is 55.

The spelling of 56554143642253 in words is "fifty-six trillion, five hundred fifty-four billion, one hundred forty-three million, six hundred forty-two thousand, two hundred fifty-three".