Base | Representation |
---|---|
bin | 110100101010111100… |
… | …011111101000101111 |
3 | 12101222102100112121202 |
4 | 310222330133220233 |
5 | 1411311044414033 |
6 | 41551523320115 |
7 | 4041326133626 |
oct | 645274375057 |
9 | 171872315552 |
10 | 56555076143 |
11 | 21a91958855 |
12 | ab6422003b |
13 | 5443b355c7 |
14 | 2a471506bd |
15 | 17100c48e8 |
hex | d2af1fa2f |
56555076143 has 2 divisors, whose sum is σ = 56555076144. Its totient is φ = 56555076142.
The previous prime is 56555076139. The next prime is 56555076191. The reversal of 56555076143 is 34167055565.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56555076143 - 22 = 56555076139 is a prime.
It is a super-3 number, since 3×565550761433 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56555076343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28277538071 + 28277538072.
It is an arithmetic number, because the mean of its divisors is an integer number (28277538072).
Almost surely, 256555076143 is an apocalyptic number.
56555076143 is a deficient number, since it is larger than the sum of its proper divisors (1).
56555076143 is an equidigital number, since it uses as much as digits as its factorization.
56555076143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1890000, while the sum is 47.
The spelling of 56555076143 in words is "fifty-six billion, five hundred fifty-five million, seventy-six thousand, one hundred forty-three".
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