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56715302456317 is a prime number
BaseRepresentation
bin11001110010101000011110…
…11101001100101111111101
321102210221002221110112112101
430321110033131030233331
524413210414412100232
6320342352242305101
714642355031455151
oct1471241735145775
9242727087415471
1056715302456317
111708690874304a
12643b980058191
1325852cb61688b
14100106cb75061
1568546630b1e7
hex33950f74cbfd

56715302456317 has 2 divisors, whose sum is σ = 56715302456318. Its totient is φ = 56715302456316.

The previous prime is 56715302456287. The next prime is 56715302456447. The reversal of 56715302456317 is 71365420351765.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31126870089316 + 25588432367001 = 5579146^2 + 5058501^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-56715302456317 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (56715302406317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28357651228158 + 28357651228159.

It is an arithmetic number, because the mean of its divisors is an integer number (28357651228159).

Almost surely, 256715302456317 is an apocalyptic number.

It is an amenable number.

56715302456317 is a deficient number, since it is larger than the sum of its proper divisors (1).

56715302456317 is an equidigital number, since it uses as much as digits as its factorization.

56715302456317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15876000, while the sum is 55.

The spelling of 56715302456317 in words is "fifty-six trillion, seven hundred fifteen billion, three hundred two million, four hundred fifty-six thousand, three hundred seventeen".