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56720333441117 = 521812110869877
BaseRepresentation
bin11001110010110001110110…
…10100111000100001011101
321102211102002120011001020202
430321120323110320201131
524413301220330103432
6320344543401553245
714642623511232263
oct1471307324704135
9242742076131222
1056720333441117
1117088a5a593425
126440944aa5825
132585920a03768
1410013c8dc0433
1568565cd33462
hex33963b53885d

56720333441117 has 4 divisors (see below), whose sum is σ = 56720349529116. Its totient is φ = 56720317353120.

The previous prime is 56720333441047. The next prime is 56720333441119. The reversal of 56720333441117 is 71114433302765.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1339514575876 + 55380818865241 = 1157374^2 + 7441829^2 .

It is a cyclic number.

It is not a de Polignac number, because 56720333441117 - 28 = 56720333440861 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (56720333441119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 216818 + ... + 10653059.

It is an arithmetic number, because the mean of its divisors is an integer number (14180087382279).

Almost surely, 256720333441117 is an apocalyptic number.

It is an amenable number.

56720333441117 is a deficient number, since it is larger than the sum of its proper divisors (16087999).

56720333441117 is a wasteful number, since it uses less digits than its factorization.

56720333441117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16087998.

The product of its (nonzero) digits is 1270080, while the sum is 47.

The spelling of 56720333441117 in words is "fifty-six trillion, seven hundred twenty billion, three hundred thirty-three million, four hundred forty-one thousand, one hundred seventeen".

Divisors: 1 5218121 10869877 56720333441117