Base | Representation |
---|---|
bin | 101001010001111001000… |
… | …0000010101010110011111 |
3 | 202002101002012000102200021 |
4 | 1102203302000111112133 |
5 | 1220423124223120242 |
6 | 20022155400013011 |
7 | 1123614363565663 |
oct | 122436200252637 |
9 | 22071065012607 |
10 | 5673417004447 |
11 | 189809aaa2145 |
12 | 777667a61167 |
13 | 322002066a2a |
14 | 1588483988a3 |
15 | 9c8a2b65b67 |
hex | 528f201559f |
5673417004447 has 2 divisors, whose sum is σ = 5673417004448. Its totient is φ = 5673417004446.
The previous prime is 5673417004429. The next prime is 5673417004523. The reversal of 5673417004447 is 7444007143765.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5673417004447 - 239 = 5123661190559 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5673417004394 and 5673417004403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5673417004417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2836708502223 + 2836708502224.
It is an arithmetic number, because the mean of its divisors is an integer number (2836708502224).
Almost surely, 25673417004447 is an apocalyptic number.
5673417004447 is a deficient number, since it is larger than the sum of its proper divisors (1).
5673417004447 is an equidigital number, since it uses as much as digits as its factorization.
5673417004447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7902720, while the sum is 52.
The spelling of 5673417004447 in words is "five trillion, six hundred seventy-three billion, four hundred seventeen million, four thousand, four hundred forty-seven".
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