Base | Representation |
---|---|
bin | 101001010010001100001… |
… | …1010001000111011001111 |
3 | 202002102202002101012211021 |
4 | 1102210120122020323033 |
5 | 1220430434143203003 |
6 | 20022343333335011 |
7 | 1123636346206615 |
oct | 122443032107317 |
9 | 22072662335737 |
10 | 5674061303503 |
11 | 18983a07575aa |
12 | 777807797467 |
13 | 3220a56a2b88 |
14 | 1588a9b936b5 |
15 | 9c8de4d42bd |
hex | 52918688ecf |
5674061303503 has 2 divisors, whose sum is σ = 5674061303504. Its totient is φ = 5674061303502.
The previous prime is 5674061303467. The next prime is 5674061303513. The reversal of 5674061303503 is 3053031604765.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5674061303503 - 233 = 5665471368911 is a prime.
It is a super-3 number, since 3×56740613035033 (a number of 39 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5674061303503.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5674061303513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2837030651751 + 2837030651752.
It is an arithmetic number, because the mean of its divisors is an integer number (2837030651752).
Almost surely, 25674061303503 is an apocalyptic number.
5674061303503 is a deficient number, since it is larger than the sum of its proper divisors (1).
5674061303503 is an equidigital number, since it uses as much as digits as its factorization.
5674061303503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 680400, while the sum is 43.
The spelling of 5674061303503 in words is "five trillion, six hundred seventy-four billion, sixty-one million, three hundred three thousand, five hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •