Base | Representation |
---|---|
bin | 110100111010011010… |
… | …110001110111111011 |
3 | 12102122111211110010002 |
4 | 310322122301313323 |
5 | 1412324024022103 |
6 | 42033355343215 |
7 | 4050630520145 |
oct | 647232616773 |
9 | 172574743102 |
10 | 56814673403 |
11 | 22105447044 |
12 | b017151b0b |
13 | 5485858457 |
14 | 2a6d807c95 |
15 | 1727ca2488 |
hex | d3a6b1dfb |
56814673403 has 2 divisors, whose sum is σ = 56814673404. Its totient is φ = 56814673402.
The previous prime is 56814673367. The next prime is 56814673541. The reversal of 56814673403 is 30437641865.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56814673403 - 214 = 56814657019 is a prime.
It is a super-2 number, since 2×568146734032 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (56814673103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28407336701 + 28407336702.
It is an arithmetic number, because the mean of its divisors is an integer number (28407336702).
Almost surely, 256814673403 is an apocalyptic number.
56814673403 is a deficient number, since it is larger than the sum of its proper divisors (1).
56814673403 is an equidigital number, since it uses as much as digits as its factorization.
56814673403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1451520, while the sum is 47.
The spelling of 56814673403 in words is "fifty-six billion, eight hundred fourteen million, six hundred seventy-three thousand, four hundred three".
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