Base | Representation |
---|---|
bin | 110101000000011010… |
… | …100111100010000111 |
3 | 12102220112011112002120 |
4 | 311000122213202013 |
5 | 1413030303404333 |
6 | 42051352141023 |
7 | 4053262006515 |
oct | 650032474207 |
9 | 172815145076 |
10 | 56915294343 |
11 | 22157222046 |
12 | b044997773 |
13 | 54a065877b |
14 | 2a7cd1b4b5 |
15 | 1731a2adb3 |
hex | d406a7887 |
56915294343 has 4 divisors (see below), whose sum is σ = 75887059128. Its totient is φ = 37943529560.
The previous prime is 56915294341. The next prime is 56915294369. The reversal of 56915294343 is 34349251965.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 56915294343 - 21 = 56915294341 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (56915294341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9485882388 + ... + 9485882393.
It is an arithmetic number, because the mean of its divisors is an integer number (18971764782).
Almost surely, 256915294343 is an apocalyptic number.
56915294343 is a deficient number, since it is larger than the sum of its proper divisors (18971764785).
56915294343 is a wasteful number, since it uses less digits than its factorization.
56915294343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18971764784.
The product of its digits is 3499200, while the sum is 51.
The spelling of 56915294343 in words is "fifty-six billion, nine hundred fifteen million, two hundred ninety-four thousand, three hundred forty-three".
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