Base | Representation |
---|---|
bin | 101001011110010010100… |
… | …0101010110000110101111 |
3 | 202011220210211221202122121 |
4 | 1102330211011112012233 |
5 | 1221342142200310142 |
6 | 20042321451453411 |
7 | 1125546253354030 |
oct | 122744505260657 |
9 | 22156724852577 |
10 | 5700043760047 |
11 | 18a841411478a |
12 | 780859157267 |
13 | 324686613310 |
14 | 159c527dca87 |
15 | 9d41056ec67 |
hex | 52f251561af |
5700043760047 has 16 divisors (see below), whose sum is σ = 7018305702912. Its totient is φ = 4508081514720.
The previous prime is 5700043760017. The next prime is 5700043760051. The reversal of 5700043760047 is 7400673400075.
It is a de Polignac number, because none of the positive numbers 2k-5700043760047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5700043759985 and 5700043760012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5700043760017) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12576229 + ... + 13021582.
It is an arithmetic number, because the mean of its divisors is an integer number (438644106432).
Almost surely, 25700043760047 is an apocalyptic number.
5700043760047 is a deficient number, since it is larger than the sum of its proper divisors (1318261942865).
5700043760047 is a wasteful number, since it uses less digits than its factorization.
5700043760047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25600278.
The product of its (nonzero) digits is 493920, while the sum is 43.
The spelling of 5700043760047 in words is "five trillion, seven hundred billion, forty-three million, seven hundred sixty thousand, forty-seven".
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