Base | Representation |
---|---|
bin | 11001111011010000011000… |
… | …01100101100110110011101 |
3 | 21110212020220110120220001210 |
4 | 30331220030030230312131 |
5 | 24433034224214340013 |
6 | 321130433454455033 |
7 | 15002644415604645 |
oct | 1475501414546635 |
9 | 243766813526053 |
10 | 57011600543133 |
11 | 17190536243165 |
12 | 6489291804479 |
13 | 25a722b501ac2 |
14 | 101153a399525 |
15 | 68d0089c6cc3 |
hex | 33da0c32cd9d |
57011600543133 has 4 divisors (see below), whose sum is σ = 76015467390848. Its totient is φ = 38007733695420.
The previous prime is 57011600543123. The next prime is 57011600543141. The reversal of 57011600543133 is 33134500611075.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 57011600543133 - 29 = 57011600542621 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 57011600543091 and 57011600543100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (57011600543123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9501933423853 + ... + 9501933423858.
It is an arithmetic number, because the mean of its divisors is an integer number (19003866847712).
Almost surely, 257011600543133 is an apocalyptic number.
It is an amenable number.
57011600543133 is a deficient number, since it is larger than the sum of its proper divisors (19003866847715).
57011600543133 is a wasteful number, since it uses less digits than its factorization.
57011600543133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19003866847714.
The product of its (nonzero) digits is 113400, while the sum is 39.
The spelling of 57011600543133 in words is "fifty-seven trillion, eleven billion, six hundred million, five hundred forty-three thousand, one hundred thirty-three".
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