Base | Representation |
---|---|
bin | 11001111011110100110100… |
… | …11011110000110110011011 |
3 | 21110221010102001210221102221 |
4 | 30331322122123300312123 |
5 | 24433344312140204111 |
6 | 321143431210004511 |
7 | 15004236322451335 |
oct | 1475723233606633 |
9 | 243833361727387 |
10 | 57031166725531 |
11 | 171988668a9639 |
12 | 6491032416737 |
13 | 25a902905761b |
14 | 1012474bd6455 |
15 | 68d7a15ee371 |
hex | 33de9a6f0d9b |
57031166725531 has 2 divisors, whose sum is σ = 57031166725532. Its totient is φ = 57031166725530.
The previous prime is 57031166725529. The next prime is 57031166725619. The reversal of 57031166725531 is 13552766113075.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 57031166725531 - 21 = 57031166725529 is a prime.
It is a super-2 number, since 2×570311667255312 (a number of 28 digits) contains 22 as substring.
Together with 57031166725529, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (57031166729531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28515583362765 + 28515583362766.
It is an arithmetic number, because the mean of its divisors is an integer number (28515583362766).
Almost surely, 257031166725531 is an apocalyptic number.
57031166725531 is a deficient number, since it is larger than the sum of its proper divisors (1).
57031166725531 is an equidigital number, since it uses as much as digits as its factorization.
57031166725531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3969000, while the sum is 52.
The spelling of 57031166725531 in words is "fifty-seven trillion, thirty-one billion, one hundred sixty-six million, seven hundred twenty-five thousand, five hundred thirty-one".
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