Base | Representation |
---|---|
bin | 11001111100000101100000… |
… | …10011010100000100000011 |
3 | 21110221222112021122110021022 |
4 | 30332002300103110010003 |
5 | 24434021133111400221 |
6 | 321151512045420055 |
7 | 15005004302243222 |
oct | 1476026023240403 |
9 | 243858467573238 |
10 | 57040123543811 |
11 | 171a16427867a1 |
12 | 6492911b6a62b |
13 | 25a9b25898ab5 |
14 | 1012a845aacb9 |
15 | 68db27aeb4ab |
hex | 33e0b04d4103 |
57040123543811 has 2 divisors, whose sum is σ = 57040123543812. Its totient is φ = 57040123543810.
The previous prime is 57040123543757. The next prime is 57040123543813. The reversal of 57040123543811 is 11834532104075.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 57040123543811 - 26 = 57040123543747 is a prime.
Together with 57040123543813, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (57040123543813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28520061771905 + 28520061771906.
It is an arithmetic number, because the mean of its divisors is an integer number (28520061771906).
Almost surely, 257040123543811 is an apocalyptic number.
57040123543811 is a deficient number, since it is larger than the sum of its proper divisors (1).
57040123543811 is an equidigital number, since it uses as much as digits as its factorization.
57040123543811 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 403200, while the sum is 44.
Adding to 57040123543811 its reverse (11834532104075), we get a palindrome (68874655647886).
The spelling of 57040123543811 in words is "fifty-seven trillion, forty billion, one hundred twenty-three million, five hundred forty-three thousand, eight hundred eleven".
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