Base | Representation |
---|---|
bin | 110101001000000100… |
… | …100110010111101011 |
3 | 12110020110212020121021 |
4 | 311020010212113223 |
5 | 1413311144141024 |
6 | 42112221153311 |
7 | 4056411535201 |
oct | 651004462753 |
9 | 173213766537 |
10 | 57043740139 |
11 | 222127822a1 |
12 | b07b9bb837 |
13 | 54c114b9b9 |
14 | 2a91dd5071 |
15 | 173ce4dde4 |
hex | d481265eb |
57043740139 has 4 divisors (see below), whose sum is σ = 57059990800. Its totient is φ = 57027489480.
The previous prime is 57043740137. The next prime is 57043740151. The reversal of 57043740139 is 93104734075.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 57043740139 - 21 = 57043740137 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 57043740095 and 57043740104.
It is not an unprimeable number, because it can be changed into a prime (57043740137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8120064 + ... + 8127085.
It is an arithmetic number, because the mean of its divisors is an integer number (14264997700).
Almost surely, 257043740139 is an apocalyptic number.
57043740139 is a deficient number, since it is larger than the sum of its proper divisors (16250661).
57043740139 is a wasteful number, since it uses less digits than its factorization.
57043740139 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16250660.
The product of its (nonzero) digits is 317520, while the sum is 43.
The spelling of 57043740139 in words is "fifty-seven billion, forty-three million, seven hundred forty thousand, one hundred thirty-nine".
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