Base | Representation |
---|---|
bin | 1010101000010100… |
… | …00101110000000001 |
3 | 112201201112110220122 |
4 | 11110022011300001 |
5 | 43141431222213 |
6 | 2342142350025 |
7 | 261264556565 |
oct | 52412056001 |
9 | 15651473818 |
10 | 5706898433 |
11 | 2469439295 |
12 | 113328b315 |
13 | 6cc444ba2 |
14 | 3c1d136a5 |
15 | 23603cd08 |
hex | 154285c01 |
5706898433 has 2 divisors, whose sum is σ = 5706898434. Its totient is φ = 5706898432.
The previous prime is 5706898409. The next prime is 5706898471. The reversal of 5706898433 is 3348986075.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3515066944 + 2191831489 = 59288^2 + 46817^2 .
It is a cyclic number.
It is not a de Polignac number, because 5706898433 - 28 = 5706898177 is a prime.
It is not a weakly prime, because it can be changed into another prime (5706898333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2853449216 + 2853449217.
It is an arithmetic number, because the mean of its divisors is an integer number (2853449217).
Almost surely, 25706898433 is an apocalyptic number.
It is an amenable number.
5706898433 is a deficient number, since it is larger than the sum of its proper divisors (1).
5706898433 is an equidigital number, since it uses as much as digits as its factorization.
5706898433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4354560, while the sum is 53.
The square root of 5706898433 is about 75544.0165267905. The cubic root of 5706898433 is about 1787.0363276658.
The spelling of 5706898433 in words is "five billion, seven hundred six million, eight hundred ninety-eight thousand, four hundred thirty-three".
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