57111969853 has 4 divisors (see below), whose sum is σ = 57271056480. Its totient is φ = 56952883228.

The previous prime is 57111969809. The next prime is 57111969911. The reversal of 57111969853 is 35896911175.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 57111969853 - 2¹⁷ = 57111838781 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 57111969794 and 57111969803.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (57111961853) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79542775 + ... + 79543492.

It is an arithmetic number, because the mean of its divisors is an integer number (14317764120).

Almost surely, 2^57111969853 is an apocalyptic number.

It is an amenable number.

57111969853 is a deficient number, since it is larger than the sum of its proper divisors (159086627).

57111969853 is a wasteful number, since it uses less digits than its factorization.

57111969853 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 159086626.

The product of its digits is 2041200, while the sum is 55.

The spelling of 57111969853 in words is "fifty-seven billion, one hundred eleven million, nine hundred sixty-nine thousand, eight hundred fifty-three".