Base | Representation |
---|---|
bin | 11001111110010001111101… |
… | …11000111011011011110011 |
3 | 21111020012011111121011002212 |
4 | 30333020332320323123303 |
5 | 24441240101213304412 |
6 | 321250302400202335 |
7 | 15013314040330142 |
oct | 1477107670733363 |
9 | 244205144534085 |
10 | 57115530213107 |
11 | 172206188964a3 |
12 | 64a54576093ab |
13 | 25b3c821aa142 |
14 | 10165992a3759 |
15 | 690a8cbe3222 |
hex | 33f23ee3b6f3 |
57115530213107 has 4 divisors (see below), whose sum is σ = 59598814135440. Its totient is φ = 54632246290776.
The previous prime is 57115530213073. The next prime is 57115530213109. The reversal of 57115530213107 is 70131203551175.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 57115530213107 - 212 = 57115530209011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (57115530213109) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1241641961132 + ... + 1241641961177.
It is an arithmetic number, because the mean of its divisors is an integer number (14899703533860).
Almost surely, 257115530213107 is an apocalyptic number.
57115530213107 is a deficient number, since it is larger than the sum of its proper divisors (2483283922333).
57115530213107 is a wasteful number, since it uses less digits than its factorization.
57115530213107 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2483283922332.
The product of its (nonzero) digits is 110250, while the sum is 41.
The spelling of 57115530213107 in words is "fifty-seven trillion, one hundred fifteen billion, five hundred thirty million, two hundred thirteen thousand, one hundred seven".
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