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57145886953 is a prime number
BaseRepresentation
bin110101001110001010…
…010000100011101001
312110111121001211200121
4311032022100203221
51414013321340303
642130310403241
74062062011261
oct651612204351
9173447054617
1057145886953
11222653aa751
12b0aa060521
1355093646bc
142aa17c47a1
151746dc99bd
hexd4e2908e9

57145886953 has 2 divisors, whose sum is σ = 57145886954. Its totient is φ = 57145886952.

The previous prime is 57145886951. The next prime is 57145887013. The reversal of 57145886953 is 35968854175.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 40163366464 + 16982520489 = 200408^2 + 130317^2 .

It is a cyclic number.

It is not a de Polignac number, because 57145886953 - 21 = 57145886951 is a prime.

It is a super-3 number, since 3×571458869533 (a number of 33 digits) contains 333 as substring.

Together with 57145886951, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 57145886891 and 57145886900.

It is not a weakly prime, because it can be changed into another prime (57145886951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28572943476 + 28572943477.

It is an arithmetic number, because the mean of its divisors is an integer number (28572943477).

Almost surely, 257145886953 is an apocalyptic number.

It is an amenable number.

57145886953 is a deficient number, since it is larger than the sum of its proper divisors (1).

57145886953 is an equidigital number, since it uses as much as digits as its factorization.

57145886953 is an evil number, because the sum of its binary digits is even.

The product of its digits is 36288000, while the sum is 61.

The spelling of 57145886953 in words is "fifty-seven billion, one hundred forty-five million, eight hundred eighty-six thousand, nine hundred fifty-three".