57153011113 has 4 divisors (see below), whose sum is σ = 62348739408. Its totient is φ = 51957282820.

The previous prime is 57153011101. The next prime is 57153011119. The reversal of 57153011113 is 31111035175.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 57153011113 - 2⁵ = 57153011081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (57153011119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2597864131 + ... + 2597864152.

It is an arithmetic number, because the mean of its divisors is an integer number (15587184852).

Almost surely, 2^57153011113 is an apocalyptic number.

It is an amenable number.

57153011113 is a deficient number, since it is larger than the sum of its proper divisors (5195728295).

57153011113 is a wasteful number, since it uses less digits than its factorization.

57153011113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5195728294.

The product of its (nonzero) digits is 1575, while the sum is 28.

Adding to 57153011113 its reverse (31111035175), we get a palindrome (88264046288).

The spelling of 57153011113 in words is "fifty-seven billion, one hundred fifty-three million, eleven thousand, one hundred thirteen".