Base | Representation |
---|---|
bin | 110101011000000100… |
… | …011011110000010101 |
3 | 12110221011212222011220 |
4 | 311120010123300111 |
5 | 1414333401211432 |
6 | 42155005520553 |
7 | 4066151041122 |
oct | 653004336025 |
9 | 173834788156 |
10 | 57312132117 |
11 | 22340228149 |
12 | b135873159 |
13 | 5534930916 |
14 | 2ab98db749 |
15 | 17567b772c |
hex | d5811bc15 |
57312132117 has 4 divisors (see below), whose sum is σ = 76416176160. Its totient is φ = 38208088076.
The previous prime is 57312132107. The next prime is 57312132127. The reversal of 57312132117 is 71123121375.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (57312132107) and next prime (57312132127).
It is a cyclic number.
It is not a de Polignac number, because 57312132117 - 227 = 57177914389 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (57312132107) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9552022017 + ... + 9552022022.
It is an arithmetic number, because the mean of its divisors is an integer number (19104044040).
Almost surely, 257312132117 is an apocalyptic number.
It is an amenable number.
57312132117 is a deficient number, since it is larger than the sum of its proper divisors (19104044043).
57312132117 is a wasteful number, since it uses less digits than its factorization.
57312132117 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19104044042.
The product of its digits is 8820, while the sum is 33.
The spelling of 57312132117 in words is "fifty-seven billion, three hundred twelve million, one hundred thirty-two thousand, one hundred seventeen".
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