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5733312161472 = 2632721110096679
BaseRepresentation
bin101001101101110010000…
…0010001110011011000000
3202022002200101022122220100
41103123210002032123000
51222413310403131342
620105503001042400
71131134551201020
oct123334402163300
922262611278810
105733312161472
111910536280115
127871a2786400
13327858b75c4c
1415b6cad59a80
159e20b0a8e4c
hex536e408e6c0

5733312161472 has 336 divisors, whose sum is σ = 18891687692800. Its totient is φ = 1628466094080.

The previous prime is 5733312161449. The next prime is 5733312161477. The reversal of 5733312161472 is 2741612133375.

5733312161472 is a `hidden beast` number, since 5 + 7 + 3 + 3 + 3 + 1 + 21 + 614 + 7 + 2 = 666.

It is a tau number, because it is divible by the number of its divisors (336).

It is not an unprimeable number, because it can be changed into a prime (5733312161477) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 858405429 + ... + 858412107.

Almost surely, 25733312161472 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 5733312161472, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (9445843846400).

5733312161472 is an abundant number, since it is smaller than the sum of its proper divisors (13158375531328).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

5733312161472 is a wasteful number, since it uses less digits than its factorization.

5733312161472 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7924 (or 7911 counting only the distinct ones).

The product of its digits is 635040, while the sum is 45.

The spelling of 5733312161472 in words is "five trillion, seven hundred thirty-three billion, three hundred twelve million, one hundred sixty-one thousand, four hundred seventy-two".