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5734501433 is a prime number
BaseRepresentation
bin1010101011100110…
…11000110000111001
3112210122110212002222
411111303120300321
543221013021213
62345010133425
7262051313033
oct52563306071
915718425088
105734501433
112482a81891
121140581275
1370508ab1b
143c585ac53
15238691808
hex155cd8c39

5734501433 has 2 divisors, whose sum is σ = 5734501434. Its totient is φ = 5734501432.

The previous prime is 5734501417. The next prime is 5734501447. The reversal of 5734501433 is 3341054375.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4133461264 + 1601040169 = 64292^2 + 40013^2 .

It is a cyclic number.

It is not a de Polignac number, because 5734501433 - 24 = 5734501417 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5734501393 and 5734501402.

It is not a weakly prime, because it can be changed into another prime (5734531433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2867250716 + 2867250717.

It is an arithmetic number, because the mean of its divisors is an integer number (2867250717).

Almost surely, 25734501433 is an apocalyptic number.

It is an amenable number.

5734501433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5734501433 is an equidigital number, since it uses as much as digits as its factorization.

5734501433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 75600, while the sum is 35.

The square root of 5734501433 is about 75726.4909592409. The cubic root of 5734501433 is about 1789.9128608372.

The spelling of 5734501433 in words is "five billion, seven hundred thirty-four million, five hundred one thousand, four hundred thirty-three".