Base | Representation |
---|---|
bin | 110101011101101001… |
… | …011010100010000001 |
3 | 12111011200222100100111 |
4 | 311131221122202001 |
5 | 1420031330300023 |
6 | 42212151351321 |
7 | 4101365335222 |
oct | 653551324201 |
9 | 174150870314 |
10 | 57405712513 |
11 | 22389034516 |
12 | b161082541 |
13 | 554b137436 |
14 | 2ac80db249 |
15 | 175eb0000d |
hex | d5da5a881 |
57405712513 has 2 divisors, whose sum is σ = 57405712514. Its totient is φ = 57405712512.
The previous prime is 57405712501. The next prime is 57405712537. The reversal of 57405712513 is 31521750475.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 36851329089 + 20554383424 = 191967^2 + 143368^2 .
It is a cyclic number.
It is not a de Polignac number, because 57405712513 - 221 = 57403615361 is a prime.
It is not a weakly prime, because it can be changed into another prime (57405712543) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28702856256 + 28702856257.
It is an arithmetic number, because the mean of its divisors is an integer number (28702856257).
Almost surely, 257405712513 is an apocalyptic number.
It is an amenable number.
57405712513 is a deficient number, since it is larger than the sum of its proper divisors (1).
57405712513 is an equidigital number, since it uses as much as digits as its factorization.
57405712513 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 147000, while the sum is 40.
The spelling of 57405712513 in words is "fifty-seven billion, four hundred five million, seven hundred twelve thousand, five hundred thirteen".
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