Base | Representation |
---|---|
bin | 110101100010011000… |
… | …101101011001011001 |
3 | 12111101020120201022122 |
4 | 311202120231121121 |
5 | 1420212204010132 |
6 | 42224111431025 |
7 | 4103352205613 |
oct | 654230553131 |
9 | 174336521278 |
10 | 57485219417 |
11 | 224199a91aa |
12 | b183825475 |
13 | 5561754242 |
14 | 2ad48b5db3 |
15 | 1766aa7912 |
hex | d6262d659 |
57485219417 has 2 divisors, whose sum is σ = 57485219418. Its totient is φ = 57485219416.
The previous prime is 57485219413. The next prime is 57485219453. The reversal of 57485219417 is 71491258475.
It is a happy number.
57485219417 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 53021509696 + 4463709721 = 230264^2 + 66811^2 .
It is a cyclic number.
It is not a de Polignac number, because 57485219417 - 22 = 57485219413 is a prime.
It is not a weakly prime, because it can be changed into another prime (57485219413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28742609708 + 28742609709.
It is an arithmetic number, because the mean of its divisors is an integer number (28742609709).
Almost surely, 257485219417 is an apocalyptic number.
It is an amenable number.
57485219417 is a deficient number, since it is larger than the sum of its proper divisors (1).
57485219417 is an equidigital number, since it uses as much as digits as its factorization.
57485219417 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2822400, while the sum is 53.
The spelling of 57485219417 in words is "fifty-seven billion, four hundred eighty-five million, two hundred nineteen thousand, four hundred seventeen".
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