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57546603397 is a prime number
BaseRepresentation
bin110101100110000010…
…110111101110000101
312111112112002100022101
4311212002313232011
51420323412302042
642234143232101
74105026025633
oct654602675605
9174475070271
1057546603397
1122450614968
12b1a02a8631
13557139711a
142adcad4353
15176c1806b7
hexd660b7b85

57546603397 has 2 divisors, whose sum is σ = 57546603398. Its totient is φ = 57546603396.

The previous prime is 57546603379. The next prime is 57546603403. The reversal of 57546603397 is 79330664575.

Together with previous prime (57546603379) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40642963201 + 16903640196 = 201601^2 + 130014^2 .

It is a cyclic number.

It is not a de Polignac number, because 57546603397 - 215 = 57546570629 is a prime.

It is a super-2 number, since 2×575466033972 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (57546603337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28773301698 + 28773301699.

It is an arithmetic number, because the mean of its divisors is an integer number (28773301699).

Almost surely, 257546603397 is an apocalyptic number.

It is an amenable number.

57546603397 is a deficient number, since it is larger than the sum of its proper divisors (1).

57546603397 is an equidigital number, since it uses as much as digits as its factorization.

57546603397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14288400, while the sum is 55.

The spelling of 57546603397 in words is "fifty-seven billion, five hundred forty-six million, six hundred three thousand, three hundred ninety-seven".