Base | Representation |
---|---|
bin | 101001111010101111101… |
… | …1011001010101100000101 |
3 | 202101202112121002010112101 |
4 | 1103311133123022230011 |
5 | 1223342314414214000 |
6 | 20130345311352101 |
7 | 1133141501604601 |
oct | 123653733125405 |
9 | 22352477063471 |
10 | 5761152101125 |
11 | 1921322193903 |
12 | 790672222631 |
13 | 32a374881915 |
14 | 15cbac562501 |
15 | 9ecda254e6a |
hex | 53d5f6cab05 |
5761152101125 has 16 divisors (see below), whose sum is σ = 7190041936896. Its totient is φ = 4608842120400.
The previous prime is 5761152101101. The next prime is 5761152101153. The reversal of 5761152101125 is 5211012511675.
It is not a de Polignac number, because 5761152101125 - 211 = 5761152099077 is a prime.
It is a super-3 number, since 3×57611521011253 (a number of 39 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7496524 + ... + 8229226.
It is an arithmetic number, because the mean of its divisors is an integer number (449377621056).
Almost surely, 25761152101125 is an apocalyptic number.
It is an amenable number.
5761152101125 is a deficient number, since it is larger than the sum of its proper divisors (1428889835771).
5761152101125 is an equidigital number, since it uses as much as digits as its factorization.
5761152101125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 795621 (or 795611 counting only the distinct ones).
The product of its (nonzero) digits is 21000, while the sum is 37.
The spelling of 5761152101125 in words is "five trillion, seven hundred sixty-one billion, one hundred fifty-two million, one hundred one thousand, one hundred twenty-five".
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