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57814186710433 is a prime number
BaseRepresentation
bin11010010010100111010100…
…00011111101010110100001
321120200222112002001112122111
431021103222003331112201
530034211423244213213
6322543245401435321
715114636304506226
oct1511235203752641
9246628462045574
1057814186710433
111746a94a2046aa
12659893a19bb41
132634b151ba18a
14103c315da194d
156a3d2dd65a3d
hex3494ea0fd5a1

57814186710433 has 2 divisors, whose sum is σ = 57814186710434. Its totient is φ = 57814186710432.

The previous prime is 57814186710391. The next prime is 57814186710461. The reversal of 57814186710433 is 33401768141875.

57814186710433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47897085075984 + 9917101634449 = 6920772^2 + 3149143^2 .

It is a cyclic number.

It is not a de Polignac number, because 57814186710433 - 29 = 57814186709921 is a prime.

It is not a weakly prime, because it can be changed into another prime (57814186780433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28907093355216 + 28907093355217.

It is an arithmetic number, because the mean of its divisors is an integer number (28907093355217).

Almost surely, 257814186710433 is an apocalyptic number.

It is an amenable number.

57814186710433 is a deficient number, since it is larger than the sum of its proper divisors (1).

57814186710433 is an equidigital number, since it uses as much as digits as its factorization.

57814186710433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13547520, while the sum is 58.

The spelling of 57814186710433 in words is "fifty-seven trillion, eight hundred fourteen billion, one hundred eighty-six million, seven hundred ten thousand, four hundred thirty-three".