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5784073251713 is a prime number
BaseRepresentation
bin101010000101011010110…
…1000011010101110000001
3202110221201000021020001122
41110022311220122232001
51224231240223023323
620145055551242025
71134612504302531
oct124126550325601
922427630236048
105784073251713
111930014618569
12794baa519315
1332c5884c4313
1415dd447a74c1
15a06cc68bec8
hex542b5a1ab81

5784073251713 has 2 divisors, whose sum is σ = 5784073251714. Its totient is φ = 5784073251712.

The previous prime is 5784073251701. The next prime is 5784073251763. The reversal of 5784073251713 is 3171523704875.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3566764633744 + 2217308617969 = 1888588^2 + 1489063^2 .

It is a cyclic number.

It is not a de Polignac number, because 5784073251713 - 214 = 5784073235329 is a prime.

It is not a weakly prime, because it can be changed into another prime (5784073251763) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2892036625856 + 2892036625857.

It is an arithmetic number, because the mean of its divisors is an integer number (2892036625857).

Almost surely, 25784073251713 is an apocalyptic number.

It is an amenable number.

5784073251713 is a deficient number, since it is larger than the sum of its proper divisors (1).

5784073251713 is an equidigital number, since it uses as much as digits as its factorization.

5784073251713 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4939200, while the sum is 53.

The spelling of 5784073251713 in words is "five trillion, seven hundred eighty-four billion, seventy-three million, two hundred fifty-one thousand, seven hundred thirteen".