Base | Representation |
---|---|
bin | 10000111000111010100… |
… | …01001110000000011001 |
3 | 2001110212220201122021011 |
4 | 20130131101032000121 |
5 | 34001434234404131 |
6 | 1122331432213521 |
7 | 56632443351562 |
oct | 10343521160031 |
9 | 2043786648234 |
10 | 580311638041 |
11 | 204121877883 |
12 | 9457523a2a1 |
13 | 429529c69a5 |
14 | 20131521169 |
15 | 1016665e0b1 |
hex | 871d44e019 |
580311638041 has 2 divisors, whose sum is σ = 580311638042. Its totient is φ = 580311638040.
The previous prime is 580311638021. The next prime is 580311638047. The reversal of 580311638041 is 140836113085.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 402839012416 + 177472625625 = 634696^2 + 421275^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-580311638041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 580311637985 and 580311638003.
It is not a weakly prime, because it can be changed into another prime (580311638047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 290155819020 + 290155819021.
It is an arithmetic number, because the mean of its divisors is an integer number (290155819021).
Almost surely, 2580311638041 is an apocalyptic number.
It is an amenable number.
580311638041 is a deficient number, since it is larger than the sum of its proper divisors (1).
580311638041 is an equidigital number, since it uses as much as digits as its factorization.
580311638041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 40.
The spelling of 580311638041 in words is "five hundred eighty billion, three hundred eleven million, six hundred thirty-eight thousand, forty-one".
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