Base | Representation |
---|---|
bin | 11010011010000010110001… |
… | …11100001010110001011011 |
3 | 21121121101101210222201000022 |
4 | 31031001120330022301123 |
5 | 30102402213200302231 |
6 | 323300423112101055 |
7 | 15142244050655621 |
oct | 1515013074126133 |
9 | 247541353881008 |
10 | 58069450009691 |
11 | 1755912a73254a |
12 | 661a2b939478b |
13 | 2652c05825813 |
14 | 104a80d813511 |
15 | 6aa7bdc95c7b |
hex | 34d058f0ac5b |
58069450009691 has 2 divisors, whose sum is σ = 58069450009692. Its totient is φ = 58069450009690.
The previous prime is 58069450009661. The next prime is 58069450009733. The reversal of 58069450009691 is 19690005496085.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-58069450009691 is a prime.
It is a super-3 number, since 3×580694500096913 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (58069450009601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29034725004845 + 29034725004846.
It is an arithmetic number, because the mean of its divisors is an integer number (29034725004846).
Almost surely, 258069450009691 is an apocalyptic number.
58069450009691 is a deficient number, since it is larger than the sum of its proper divisors (1).
58069450009691 is an equidigital number, since it uses as much as digits as its factorization.
58069450009691 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20995200, while the sum is 62.
The spelling of 58069450009691 in words is "fifty-eight trillion, sixty-nine billion, four hundred fifty million, nine thousand, six hundred ninety-one".
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