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58362445121 is a prime number
BaseRepresentation
bin110110010110101011…
…000011110101000001
312120122101020101202112
4312112223003311001
51424011241220441
642451125425105
74134163412141
oct662653036501
9176571211675
1058362445121
112282a095922
12b38956b195
1356714057c6
142b791c4921
1517b8ad64eb
hexd96ac3d41

58362445121 has 2 divisors, whose sum is σ = 58362445122. Its totient is φ = 58362445120.

The previous prime is 58362445081. The next prime is 58362445123. The reversal of 58362445121 is 12154426385.

58362445121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47112873025 + 11249572096 = 217055^2 + 106064^2 .

It is a cyclic number.

It is not a de Polignac number, because 58362445121 - 214 = 58362428737 is a prime.

Together with 58362445123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (58362445123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29181222560 + 29181222561.

It is an arithmetic number, because the mean of its divisors is an integer number (29181222561).

Almost surely, 258362445121 is an apocalyptic number.

It is an amenable number.

58362445121 is a deficient number, since it is larger than the sum of its proper divisors (1).

58362445121 is an equidigital number, since it uses as much as digits as its factorization.

58362445121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 230400, while the sum is 41.

The spelling of 58362445121 in words is "fifty-eight billion, three hundred sixty-two million, four hundred forty-five thousand, one hundred twenty-one".