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5842479726737 is a prime number
BaseRepresentation
bin101010100000100111011…
…1011011100000010010001
3202200112110110100120111022
41111001032323130002101
51231210344302223422
620231555332525225
71142051044166033
oct125011673340221
922615413316438
105842479726737
111952866546735
127a438a780815
13334c35a74a04
14162ac576dc53
15a1e9a06e342
hex5504eedc091

5842479726737 has 2 divisors, whose sum is σ = 5842479726738. Its totient is φ = 5842479726736.

The previous prime is 5842479726661. The next prime is 5842479726739. The reversal of 5842479726737 is 7376279742485.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5266331932801 + 576147793936 = 2294849^2 + 759044^2 .

It is a cyclic number.

It is not a de Polignac number, because 5842479726737 - 216 = 5842479661201 is a prime.

Together with 5842479726739, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (5842479726739) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2921239863368 + 2921239863369.

It is an arithmetic number, because the mean of its divisors is an integer number (2921239863369).

Almost surely, 25842479726737 is an apocalyptic number.

It is an amenable number.

5842479726737 is a deficient number, since it is larger than the sum of its proper divisors (1).

5842479726737 is an equidigital number, since it uses as much as digits as its factorization.

5842479726737 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 995742720, while the sum is 71.

The spelling of 5842479726737 in words is "five trillion, eight hundred forty-two billion, four hundred seventy-nine million, seven hundred twenty-six thousand, seven hundred thirty-seven".