Base | Representation |
---|---|
bin | 101010100110101100010… |
… | …1010111010101111100001 |
3 | 202201210010211010002121012 |
4 | 1111031120222322233201 |
5 | 1231414110141220423 |
6 | 20241554212110305 |
7 | 1143022305241331 |
oct | 125153052725741 |
9 | 22653124102535 |
10 | 5855528070113 |
11 | 1958351a40197 |
12 | 7a6a10605395 |
13 | 336235171a57 |
14 | 1635a26c10c1 |
15 | a24b0870078 |
hex | 55358ababe1 |
5855528070113 has 2 divisors, whose sum is σ = 5855528070114. Its totient is φ = 5855528070112.
The previous prime is 5855528070017. The next prime is 5855528070179. The reversal of 5855528070113 is 3110708255585.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3104866015969 + 2750662054144 = 1762063^2 + 1658512^2 .
It is a cyclic number.
It is not a de Polignac number, because 5855528070113 - 210 = 5855528069089 is a prime.
It is not a weakly prime, because it can be changed into another prime (5855528073113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2927764035056 + 2927764035057.
It is an arithmetic number, because the mean of its divisors is an integer number (2927764035057).
Almost surely, 25855528070113 is an apocalyptic number.
It is an amenable number.
5855528070113 is a deficient number, since it is larger than the sum of its proper divisors (1).
5855528070113 is an equidigital number, since it uses as much as digits as its factorization.
5855528070113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1680000, while the sum is 50.
The spelling of 5855528070113 in words is "five trillion, eight hundred fifty-five billion, five hundred twenty-eight million, seventy thousand, one hundred thirteen".
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