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58732148147 is a prime number
BaseRepresentation
bin110110101100101101…
…010111010110110011
312121121010220020222012
4312230231113112303
51430240412220042
642551533433135
74146303010421
oct665455272663
9177533806865
1058732148147
11229a9848212
12b47133b7ab
1356ccb99baa
142bb2340111
1517db2b2e82
hexdacb575b3

58732148147 has 2 divisors, whose sum is σ = 58732148148. Its totient is φ = 58732148146.

The previous prime is 58732148081. The next prime is 58732148149. The reversal of 58732148147 is 74184123785.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 58732148147 - 214 = 58732131763 is a prime.

It is a super-2 number, since 2×587321481472 (a number of 22 digits) contains 22 as substring.

Together with 58732148149, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 58732148095 and 58732148104.

It is not a weakly prime, because it can be changed into another prime (58732148149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29366074073 + 29366074074.

It is an arithmetic number, because the mean of its divisors is an integer number (29366074074).

Almost surely, 258732148147 is an apocalyptic number.

58732148147 is a deficient number, since it is larger than the sum of its proper divisors (1).

58732148147 is an equidigital number, since it uses as much as digits as its factorization.

58732148147 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1505280, while the sum is 50.

The spelling of 58732148147 in words is "fifty-eight billion, seven hundred thirty-two million, one hundred forty-eight thousand, one hundred forty-seven".