Base | Representation |
---|---|
bin | 110110110000011001… |
… | …010111011011001101 |
3 | 12121202110022101112101 |
4 | 312300121113123031 |
5 | 1430402231430123 |
6 | 43002023435101 |
7 | 4150653606511 |
oct | 666031273315 |
9 | 177673271471 |
10 | 58794014413 |
11 | 22a30763262 |
12 | b489bb5a91 |
13 | 570c94b454 |
14 | 2bba646141 |
15 | 17e1933aad |
hex | db06576cd |
58794014413 has 2 divisors, whose sum is σ = 58794014414. Its totient is φ = 58794014412.
The previous prime is 58794014353. The next prime is 58794014437. The reversal of 58794014413 is 31441049785.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 45221298409 + 13572716004 = 212653^2 + 116502^2 .
It is a cyclic number.
It is not a de Polignac number, because 58794014413 - 217 = 58793883341 is a prime.
It is a super-2 number, since 2×587940144132 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (58794074413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29397007206 + 29397007207.
It is an arithmetic number, because the mean of its divisors is an integer number (29397007207).
Almost surely, 258794014413 is an apocalyptic number.
It is an amenable number.
58794014413 is a deficient number, since it is larger than the sum of its proper divisors (1).
58794014413 is an equidigital number, since it uses as much as digits as its factorization.
58794014413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 483840, while the sum is 46.
The spelling of 58794014413 in words is "fifty-eight billion, seven hundred ninety-four million, fourteen thousand, four hundred thirteen".
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