Base | Representation |
---|---|
bin | 101010110101111110101… |
… | …0000101000000001100101 |
3 | 202211220212112020201211111 |
4 | 1111223331100220001211 |
5 | 1232433322133030123 |
6 | 20305023401505021 |
7 | 1145263622532133 |
oct | 125537520500145 |
9 | 22756775221744 |
10 | 5888354189413 |
11 | 1970267481503 |
12 | 7b1251aa2171 |
13 | 339366baa897 |
14 | 164dd81cc753 |
15 | a328264290d |
hex | 55afd428065 |
5888354189413 has 2 divisors, whose sum is σ = 5888354189414. Its totient is φ = 5888354189412.
The previous prime is 5888354189401. The next prime is 5888354189483. The reversal of 5888354189413 is 3149814538885.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4937559531844 + 950794657569 = 2222062^2 + 975087^2 .
It is a cyclic number.
It is not a de Polignac number, because 5888354189413 - 217 = 5888354058341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5888354189483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2944177094706 + 2944177094707.
It is an arithmetic number, because the mean of its divisors is an integer number (2944177094707).
Almost surely, 25888354189413 is an apocalyptic number.
It is an amenable number.
5888354189413 is a deficient number, since it is larger than the sum of its proper divisors (1).
5888354189413 is an equidigital number, since it uses as much as digits as its factorization.
5888354189413 is an evil number, because the sum of its binary digits is even.
The product of its digits is 132710400, while the sum is 67.
The spelling of 5888354189413 in words is "five trillion, eight hundred eighty-eight billion, three hundred fifty-four million, one hundred eighty-nine thousand, four hundred thirteen".
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