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59012020433 = 359164378887
BaseRepresentation
bin110110111101011000…
…111111100011010001
312122022122112020120102
4312331120333203101
51431324034123213
643035412222145
74156241616542
oct667530774321
9178278466512
1059012020433
1123032824423
12b52b00a955
135745b6b3b2
142bdb5944c9
151805b48158
hexdbd63f8d1

59012020433 has 4 divisors (see below), whose sum is σ = 59176399680. Its totient is φ = 58847641188.

The previous prime is 59012020429. The next prime is 59012020451. The reversal of 59012020433 is 33402021095.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33402021095 = 56680404219.

It is a cyclic number.

It is not a de Polignac number, because 59012020433 - 22 = 59012020429 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 59012020396 and 59012020405.

It is not an unprimeable number, because it can be changed into a prime (59012020633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82189085 + ... + 82189802.

It is an arithmetic number, because the mean of its divisors is an integer number (14794099920).

Almost surely, 259012020433 is an apocalyptic number.

It is an amenable number.

59012020433 is a deficient number, since it is larger than the sum of its proper divisors (164379247).

59012020433 is a wasteful number, since it uses less digits than its factorization.

59012020433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 164379246.

The product of its (nonzero) digits is 6480, while the sum is 29.

The spelling of 59012020433 in words is "fifty-nine billion, twelve million, twenty thousand, four hundred thirty-three".

Divisors: 1 359 164378887 59012020433