Base | Representation |
---|---|
bin | 110110111110101010… |
… | …000000000110010111 |
3 | 12122101010111010202121 |
4 | 312332222000012113 |
5 | 1431400003200333 |
6 | 43041451320411 |
7 | 4156620254035 |
oct | 667652000627 |
9 | 178333433677 |
10 | 59033256343 |
11 | 23043809266 |
12 | b536150107 |
13 | 574a395219 |
14 | 2c00321555 |
15 | 180794032d |
hex | dbea80197 |
59033256343 has 2 divisors, whose sum is σ = 59033256344. Its totient is φ = 59033256342.
The previous prime is 59033256277. The next prime is 59033256391. The reversal of 59033256343 is 34365233095.
59033256343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 59033256343 - 213 = 59033248151 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 59033256343.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (59033256743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29516628171 + 29516628172.
It is an arithmetic number, because the mean of its divisors is an integer number (29516628172).
Almost surely, 259033256343 is an apocalyptic number.
59033256343 is a deficient number, since it is larger than the sum of its proper divisors (1).
59033256343 is an equidigital number, since it uses as much as digits as its factorization.
59033256343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 874800, while the sum is 43.
The spelling of 59033256343 in words is "fifty-nine billion, thirty-three million, two hundred fifty-six thousand, three hundred forty-three".
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