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59062116050213 is a prime number
BaseRepresentation
bin11010110110111011110000…
…11100100110010100100101
321202010021122102021101102112
431123131320130212110211
530220133203202101323
6325340432254250405
715304045203046613
oct1533357034462445
9252107572241375
1059062116050213
1117901114845101
12675a7731b6a05
1326c56c255a363
14108289bc0a6b3
156c651b727178
hex35b778726525

59062116050213 has 2 divisors, whose sum is σ = 59062116050214. Its totient is φ = 59062116050212.

The previous prime is 59062116050177. The next prime is 59062116050227. The reversal of 59062116050213 is 31205061126095.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51439204884769 + 7622911165444 = 7172113^2 + 2760962^2 .

It is a cyclic number.

It is not a de Polignac number, because 59062116050213 - 242 = 54664069539109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (59062116050233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29531058025106 + 29531058025107.

It is an arithmetic number, because the mean of its divisors is an integer number (29531058025107).

Almost surely, 259062116050213 is an apocalyptic number.

It is an amenable number.

59062116050213 is a deficient number, since it is larger than the sum of its proper divisors (1).

59062116050213 is an equidigital number, since it uses as much as digits as its factorization.

59062116050213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 97200, while the sum is 41.

The spelling of 59062116050213 in words is "fifty-nine trillion, sixty-two billion, one hundred sixteen million, fifty thousand, two hundred thirteen".