Base | Representation |
---|---|
bin | 110111001100000001… |
… | …011001101100100111 |
3 | 12122221202102121102112 |
4 | 313030001121230213 |
5 | 1432324404304221 |
6 | 43120021431235 |
7 | 4165312251041 |
oct | 671401315447 |
9 | 178852377375 |
10 | 59257494311 |
11 | 231493465a4 |
12 | b59926b51b |
13 | 5784987902 |
14 | 2c22012a91 |
15 | 181c48615b |
hex | dcc059b27 |
59257494311 has 2 divisors, whose sum is σ = 59257494312. Its totient is φ = 59257494310.
The previous prime is 59257494301. The next prime is 59257494347. The reversal of 59257494311 is 11349475295.
59257494311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 59257494311 - 226 = 59190385447 is a prime.
It is a super-2 number, since 2×592574943112 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 59257494311.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (59257494301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29628747155 + 29628747156.
It is an arithmetic number, because the mean of its divisors is an integer number (29628747156).
Almost surely, 259257494311 is an apocalyptic number.
59257494311 is a deficient number, since it is larger than the sum of its proper divisors (1).
59257494311 is an equidigital number, since it uses as much as digits as its factorization.
59257494311 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1360800, while the sum is 50.
The spelling of 59257494311 in words is "fifty-nine billion, two hundred fifty-seven million, four hundred ninety-four thousand, three hundred eleven".
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