Base | Representation |
---|---|
bin | 101011010111100010101… |
… | …0000101101110100111111 |
3 | 210002210220112222020100222 |
4 | 1112233011100231310333 |
5 | 1240123424324224434 |
6 | 20402103334011555 |
7 | 1153424663460266 |
oct | 126570520556477 |
9 | 23083815866328 |
10 | 5960429133119 |
11 | 199889294848a |
12 | 8032077a6bbb |
13 | 3430b217c376 |
14 | 1686b460b5dd |
15 | a509eebb72e |
hex | 56bc542dd3f |
5960429133119 has 4 divisors (see below), whose sum is σ = 5960460228744. Its totient is φ = 5960398037496.
The previous prime is 5960429133007. The next prime is 5960429133163. The reversal of 5960429133119 is 9113319240695.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5960429133119 - 216 = 5960429067583 is a prime.
It is a super-3 number, since 3×59604291331193 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5960429133719) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15258497 + ... + 15644250.
It is an arithmetic number, because the mean of its divisors is an integer number (1490115057186).
Almost surely, 25960429133119 is an apocalyptic number.
5960429133119 is a deficient number, since it is larger than the sum of its proper divisors (31095625).
5960429133119 is a wasteful number, since it uses less digits than its factorization.
5960429133119 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31095624.
The product of its (nonzero) digits is 1574640, while the sum is 53.
The spelling of 5960429133119 in words is "five trillion, nine hundred sixty billion, four hundred twenty-nine million, one hundred thirty-three thousand, one hundred nineteen".
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