Base | Representation |
---|---|
bin | 10001011000000100110… |
… | …01001011001101111001 |
3 | 2010002001210020101000121 |
4 | 20230002121023031321 |
5 | 34240214343424441 |
6 | 1134135432133241 |
7 | 61064136302236 |
oct | 10540231131571 |
9 | 2102053211017 |
10 | 597040608121 |
11 | 210226949691 |
12 | 97863837221 |
13 | 443ba7c3559 |
14 | 20c7b20c78d |
15 | 107e514add1 |
hex | 8b0264b379 |
597040608121 has 4 divisors (see below), whose sum is σ = 597042738000. Its totient is φ = 597038478244.
The previous prime is 597040608077. The next prime is 597040608149. The reversal of 597040608121 is 121806040795.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 121806040795 = 5 ⋅24361208159.
It is a cyclic number.
It is not a de Polignac number, because 597040608121 - 211 = 597040606073 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (597040608181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 566791 + ... + 1230988.
It is an arithmetic number, because the mean of its divisors is an integer number (149260684500).
Almost surely, 2597040608121 is an apocalyptic number.
It is an amenable number.
597040608121 is a deficient number, since it is larger than the sum of its proper divisors (2129879).
597040608121 is a wasteful number, since it uses less digits than its factorization.
597040608121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2129878.
The product of its (nonzero) digits is 120960, while the sum is 43.
The spelling of 597040608121 in words is "five hundred ninety-seven billion, forty million, six hundred eight thousand, one hundred twenty-one".
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