Base | Representation |
---|---|
bin | 101011011100111100011… |
… | …1000001100011001110111 |
3 | 210010220212012211021210212 |
4 | 1112321320320030121313 |
5 | 1240321210312210411 |
6 | 20411302555140035 |
7 | 1154315351003564 |
oct | 126717070143167 |
9 | 23126765737725 |
10 | 5972032538231 |
11 | 19a27a774a491 |
12 | 80550574461b |
13 | 3442110c5456 |
14 | 1690956ad86b |
15 | a552d9ec68b |
hex | 56e78e0c677 |
5972032538231 has 2 divisors, whose sum is σ = 5972032538232. Its totient is φ = 5972032538230.
The previous prime is 5972032538221. The next prime is 5972032538249. The reversal of 5972032538231 is 1328352302795.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5972032538231 - 242 = 1573986027127 is a prime.
It is a super-2 number, since 2×59720325382312 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5972032538231.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5972032538221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2986016269115 + 2986016269116.
It is an arithmetic number, because the mean of its divisors is an integer number (2986016269116).
Almost surely, 25972032538231 is an apocalyptic number.
5972032538231 is a deficient number, since it is larger than the sum of its proper divisors (1).
5972032538231 is an equidigital number, since it uses as much as digits as its factorization.
5972032538231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2721600, while the sum is 50.
The spelling of 5972032538231 in words is "five trillion, nine hundred seventy-two billion, thirty-two million, five hundred thirty-eight thousand, two hundred thirty-one".
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