Base | Representation |
---|---|
bin | 101011011100111101110… |
… | …1111001111100011101111 |
3 | 210010220222120010012020011 |
4 | 1112321323233033203233 |
5 | 1240321310103223003 |
6 | 20411311431434051 |
7 | 1154316502610413 |
oct | 126717357174357 |
9 | 23126876105204 |
10 | 5972080523503 |
11 | 19a2821844536 |
12 | 805519825927 |
13 | 34421b0267c3 |
14 | 16909bc00d43 |
15 | a5532d2a46d |
hex | 56e7bbcf8ef |
5972080523503 has 4 divisors (see below), whose sum is σ = 5973298574608. Its totient is φ = 5970862472400.
The previous prime is 5972080523501. The next prime is 5972080523509. The reversal of 5972080523503 is 3053250802795.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5972080523503 - 21 = 5972080523501 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5972080523501) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 609018198 + ... + 609028003.
It is an arithmetic number, because the mean of its divisors is an integer number (1493324643652).
Almost surely, 25972080523503 is an apocalyptic number.
5972080523503 is a deficient number, since it is larger than the sum of its proper divisors (1218051105).
5972080523503 is a wasteful number, since it uses less digits than its factorization.
5972080523503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1218051104.
The product of its (nonzero) digits is 2268000, while the sum is 49.
The spelling of 5972080523503 in words is "five trillion, nine hundred seventy-two billion, eighty million, five hundred twenty-three thousand, five hundred three".
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