Base | Representation |
---|---|
bin | 101011100010100010101… |
… | …1111011000001111110101 |
3 | 210012001220002202201100011 |
4 | 1113011011133120033311 |
5 | 1241020321124001023 |
6 | 20421012000420221 |
7 | 1155222316526503 |
oct | 127050537301765 |
9 | 23161802681304 |
10 | 5984055297013 |
11 | 19a7907236072 |
12 | 807900017671 |
13 | 3453a8b97cc1 |
14 | 1698b6333673 |
15 | a59d426650d |
hex | 571457d83f5 |
5984055297013 has 2 divisors, whose sum is σ = 5984055297014. Its totient is φ = 5984055297012.
The previous prime is 5984055296959. The next prime is 5984055297079. The reversal of 5984055297013 is 3107925504895.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4546950640164 + 1437104656849 = 2132358^2 + 1198793^2 .
It is a cyclic number.
It is not a de Polignac number, because 5984055297013 - 233 = 5975465362421 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5984055291013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2992027648506 + 2992027648507.
It is an arithmetic number, because the mean of its divisors is an integer number (2992027648507).
Almost surely, 25984055297013 is an apocalyptic number.
It is an amenable number.
5984055297013 is a deficient number, since it is larger than the sum of its proper divisors (1).
5984055297013 is an equidigital number, since it uses as much as digits as its factorization.
5984055297013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13608000, while the sum is 58.
The spelling of 5984055297013 in words is "five trillion, nine hundred eighty-four billion, fifty-five million, two hundred ninety-seven thousand, thirteen".
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