Base | Representation |
---|---|
bin | 110111111000000110… |
… | …011001000101001101 |
3 | 12201212021221101112121 |
4 | 313320012121011031 |
5 | 1440333213000023 |
6 | 43321235532541 |
7 | 4222532041246 |
oct | 677006310515 |
9 | 181767841477 |
10 | 59997000013 |
11 | 23498819135 |
12 | b764a5a151 |
13 | 5871c49852 |
14 | 2c92311ccd |
15 | 186235dd5d |
hex | df819914d |
59997000013 has 2 divisors, whose sum is σ = 59997000014. Its totient is φ = 59997000012.
The previous prime is 59996999987. The next prime is 59997000067. The reversal of 59997000013 is 31000079995.
59997000013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 58557708169 + 1439291844 = 241987^2 + 37938^2 .
It is a cyclic number.
It is not a de Polignac number, because 59997000013 - 233 = 51407065421 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (59997010013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29998500006 + 29998500007.
It is an arithmetic number, because the mean of its divisors is an integer number (29998500007).
Almost surely, 259997000013 is an apocalyptic number.
It is an amenable number.
59997000013 is a deficient number, since it is larger than the sum of its proper divisors (1).
59997000013 is an equidigital number, since it uses as much as digits as its factorization.
59997000013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 76545, while the sum is 43.
The spelling of 59997000013 in words is "fifty-nine billion, nine hundred ninety-seven million, thirteen", and thus it is an aban number.
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