Base | Representation |
---|---|
bin | 1011001011010001… |
… | …01100101011101101 |
3 | 120111011022102201021 |
4 | 11211220230223231 |
5 | 44242013304033 |
6 | 2431215414141 |
7 | 301455206434 |
oct | 54550545355 |
9 | 16434272637 |
10 | 6000134893 |
11 | 25a9a13175 |
12 | 11b5524351 |
13 | 74811529c |
14 | 40cc4611b |
15 | 251b62b2d |
hex | 165a2caed |
6000134893 has 2 divisors, whose sum is σ = 6000134894. Its totient is φ = 6000134892.
The previous prime is 6000134869. The next prime is 6000134923. The reversal of 6000134893 is 3984310006.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5999741764 + 393129 = 77458^2 + 627^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6000134893 is a prime.
It is a super-2 number, since 2×60001348932 = 72003237468392242898, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (6000134813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3000067446 + 3000067447.
It is an arithmetic number, because the mean of its divisors is an integer number (3000067447).
Almost surely, 26000134893 is an apocalyptic number.
It is an amenable number.
6000134893 is a deficient number, since it is larger than the sum of its proper divisors (1).
6000134893 is an equidigital number, since it uses as much as digits as its factorization.
6000134893 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 34.
The square root of 6000134893 is about 77460.5376498253. The cubic root of 6000134893 is about 1817.1342103328.
Adding to 6000134893 its reverse (3984310006), we get a palindrome (9984444899).
The spelling of 6000134893 in words is "six billion, one hundred thirty-four thousand, eight hundred ninety-three".
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