Base | Representation |
---|---|
bin | 101011101111011001110… |
… | …0010011101011110110111 |
3 | 210021201011201100020010001 |
4 | 1113132303202131132313 |
5 | 1241443400334334143 |
6 | 20441420153412131 |
7 | 1160220551540401 |
oct | 127366342353667 |
9 | 23251151306101 |
10 | 6011671402423 |
11 | 1a08598867885 |
12 | 81112870a047 |
13 | 347b8a3c2c8b |
14 | 16ad75d11b71 |
15 | a659d94b14d |
hex | 577b389d7b7 |
6011671402423 has 4 divisors (see below), whose sum is σ = 6011983440760. Its totient is φ = 6011359364088.
The previous prime is 6011671402411. The next prime is 6011671402441. The reversal of 6011671402423 is 3242041761106.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 6011671402423 - 213 = 6011671394231 is a prime.
It is a super-2 number, since 2×60116714024232 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6011671402403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 155990268 + ... + 156028801.
It is an arithmetic number, because the mean of its divisors is an integer number (1502995860190).
Almost surely, 26011671402423 is an apocalyptic number.
6011671402423 is a deficient number, since it is larger than the sum of its proper divisors (312038337).
6011671402423 is a wasteful number, since it uses less digits than its factorization.
6011671402423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 312038336.
The product of its (nonzero) digits is 48384, while the sum is 37.
The spelling of 6011671402423 in words is "six trillion, eleven billion, six hundred seventy-one million, four hundred two thousand, four hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •