60139484113 has 4 divisors (see below), whose sum is σ = 60351991408. Its totient is φ = 59926976820.

The previous prime is 60139484081. The next prime is 60139484143. The reversal of 60139484113 is 31148493106.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 60139484113 - 2⁵ = 60139484081 is a prime.

It is a super-3 number, since 3×60139484113³ (a number of 33 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (60139484143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106253223 + ... + 106253788.

It is an arithmetic number, because the mean of its divisors is an integer number (15087997852).

Almost surely, 2^60139484113 is an apocalyptic number.

It is an amenable number.

60139484113 is a deficient number, since it is larger than the sum of its proper divisors (212507295).

60139484113 is a wasteful number, since it uses less digits than its factorization.

60139484113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 212507294.

The product of its (nonzero) digits is 62208, while the sum is 40.

The spelling of 60139484113 in words is "sixty billion, one hundred thirty-nine million, four hundred eighty-four thousand, one hundred thirteen".