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60371436142013 is a prime number
BaseRepresentation
bin11011011101000010100100…
…00000010111110110111101
321220202110020012000120001212
431232201102000113312331
530403111200123021023
6332222131020014205
715500456316152513
oct1556412200276675
9256673205016055
1060371436142013
11182664229051a7
12693047b991365
13278c0045189c9
1410c9dc90d04b3
156ea5ed9a5e78
hex36e852017dbd

60371436142013 has 2 divisors, whose sum is σ = 60371436142014. Its totient is φ = 60371436142012.

The previous prime is 60371436141937. The next prime is 60371436142067. The reversal of 60371436142013 is 31024163417306.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44636870052889 + 15734566089124 = 6681083^2 + 3966682^2 .

It is a cyclic number.

It is not a de Polignac number, because 60371436142013 - 222 = 60371431947709 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (60371436142513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30185718071006 + 30185718071007.

It is an arithmetic number, because the mean of its divisors is an integer number (30185718071007).

Almost surely, 260371436142013 is an apocalyptic number.

It is an amenable number.

60371436142013 is a deficient number, since it is larger than the sum of its proper divisors (1).

60371436142013 is an equidigital number, since it uses as much as digits as its factorization.

60371436142013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 217728, while the sum is 41.

Adding to 60371436142013 its reverse (31024163417306), we get a palindrome (91395599559319).

The spelling of 60371436142013 in words is "sixty trillion, three hundred seventy-one billion, four hundred thirty-six million, one hundred forty-two thousand, thirteen".