Base | Representation |
---|---|
bin | 111000110011000000… |
… | …111011000010011111 |
3 | 12211102011211102120201 |
4 | 320303000323002133 |
5 | 1444344232000413 |
6 | 44003305124331 |
7 | 4256163351043 |
oct | 706300730237 |
9 | 184364742521 |
10 | 60985421983 |
11 | 239557541a2 |
12 | b99ba896a7 |
13 | 599b961b15 |
14 | 2d476c8023 |
15 | 18be0049dd |
hex | e3303b09f |
60985421983 has 2 divisors, whose sum is σ = 60985421984. Its totient is φ = 60985421982.
The previous prime is 60985421963. The next prime is 60985422031. The reversal of 60985421983 is 38912458906.
60985421983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 60985421983 - 25 = 60985421951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (60985421923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30492710991 + 30492710992.
It is an arithmetic number, because the mean of its divisors is an integer number (30492710992).
Almost surely, 260985421983 is an apocalyptic number.
60985421983 is a deficient number, since it is larger than the sum of its proper divisors (1).
60985421983 is an equidigital number, since it uses as much as digits as its factorization.
60985421983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3732480, while the sum is 55.
The spelling of 60985421983 in words is "sixty billion, nine hundred eighty-five million, four hundred twenty-one thousand, nine hundred eighty-three".
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